The magnitude of crystal field stabilisa...

The magnitude of crystal field stabilisation energy (CFSE of `Delta_(1)`) in tetrahedral complexes is considerably less than that in the octahderal field. Because

There are only four ligands instead of six so the ligand field is only 2/3 the size hence the `Delta_(t)` is only 2/3 the size

The direction of the orbitals does not coincide with the direction of the ligands. This reduces the crystal field stabilization energy `(Delta_(t))` by further 2/3

Both points (a) and (b) are correct

Both points (a) and (b) are wrong

Text Solution

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The correct Answer is:

CFSE in case of tetrahedral complexes is less than the octahedral field due to the points (a) and (b).

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The magnitude of crystal field stabilization energy (CFSE or Delta t) in tetrahedral complexes is considerably less than in octahedral field. This is because

There are four ligands instead of six so the ligand field is only 2/3 the size hence , the `Delta`t is only 2//3 the size

The direction of the orbitals does not coincide with the direction fo the ligands . This reduces the crystal field stabilisation energy `(Deltat)` by further 2/3

Both points (A) and (B) correct

Both points (A) and (B) are wrong .

The magnitude of crystal field stabilization energy (CFSE) in tetrahedral complexes is considerably less than in the octahedral field beause

There are only four ligands instead of six so the ligand field is only `2//3` the size hence the `Delta_(t)` is only `2//3` the size

The direction of the orbitals does not coincide with the direction of the ligands. This reduces the crystal field stabilization energy `Delta_(t)` by further `2//3` .

Both points (1) and (2) are correct

Both points (1) and (2) are wrong

The magnitude of crystal field stabilization energy depends on

The nature of of ligands

The charge on the metals atom

The charge on the ligand

Position of metal in periodic table