Give the IUPAC names off the following:
(i) `CH_(3)CH_(2)-underset(Br)underset(|)overset(CH_(3))overset(|)(C)-underset(Br)underset(|)(C)H-CH_(2)-Cl`
(ii) `CH_(3)-underset(Cl)underset(|)overset(C_(2)H_(5))overset(|)(C)-CH_(2)-underset(Cl)underset(|)overset(C_(2)H_(5))overset(|)(C)-CH_(3)`
(iii) `CH_(2)=CHCH_(2)Br`
(iv) `(CH_(3))_(3)C CH_(2)Br`.

Answer

To determine the IUPAC names for the given compounds, we will follow the standard rules for naming organic compounds, particularly focusing on haloalkanes. Let's break down each compound step by step.

### (i) `CH₃CH₂- Br | CH₃ | (C)- Br | CH-CH₂-Cl`

1. **Identify the longest carbon chain**: The longest chain contains 6 carbon atoms.
2. **Number the carbon chain**: Start numbering from the end closest to the first substituent (Br or Cl). The numbering is as follows:
- 1 (Br), 2 (C), 3 (C), 4 (Br), 5 (C), 6 (Cl).
3. **Identify and name the substituents**:
- There are two bromine (Br) substituents at positions 1 and 4, and one chlorine (Cl) substituent at position 6, and a methyl (CH₃) group at position 3.
4. **Combine the names**: The name will include the substituents in alphabetical order, followed by the base name of the longest chain.
5. **Final IUPAC name**: 4-Bromo-1-bromo-3-methyl-hexane.

### (ii) `CH₃- Cl | (C₂H₅) | (C)-CH₂-Cl | (C₂H₅) | (C)-CH₃`

1. **Identify the longest carbon chain**: The longest chain contains 5 carbon atoms.
2. **Number the carbon chain**: Start numbering from the end closest to the first substituent (Cl). The numbering is as follows:
- 1 (Cl), 2 (C₂H₅), 3 (C), 4 (C₂H₅), 5 (C).
3. **Identify and name the substituents**:
- There are two chlorine (Cl) substituents at positions 1 and 4, and two ethyl (C₂H₅) groups at positions 2 and 4.
4. **Combine the names**: The name will include the substituents in alphabetical order, followed by the base name of the longest chain.
5. **Final IUPAC name**: 1,4-Dichloro-2,3-diethylpentane.

### (iii) `CH₂=CHCH₂Br`

1. **Identify the longest carbon chain**: The longest chain contains 3 carbon atoms with a double bond.
2. **Number the carbon chain**: Start numbering from the end of the double bond. The numbering is as follows:
- 1 (C=C), 2 (C), 3 (Br).
3. **Identify and name the substituents**: There is one bromine (Br) substituent at position 3.
4. **Combine the names**: The name will include the double bond position and the substituent.
5. **Final IUPAC name**: 3-Bromoprop-1-ene.

### (iv) `(CH₃)₃C CH₂Br`

1. **Identify the longest carbon chain**: The longest chain contains 4 carbon atoms.
2. **Number the carbon chain**: Start numbering from the end closest to the first substituent (Br). The numbering is as follows:
- 1 (Br), 2 (C), 3 (C), 4 (C).
3. **Identify and name the substituents**: There is one bromine (Br) substituent at position 1 and three methyl (CH₃) groups at position 2.
4. **Combine the names**: The name will include the substituents in alphabetical order, followed by the base name of the longest chain.
5. **Final IUPAC name**: 1-Bromo-2,2,3-trimethylbutane.

### Summary of IUPAC Names:
1. 4-Bromo-1-bromo-3-methyl-hexane
2. 1,4-Dichloro-2,3-diethylpentane
3. 3-Bromoprop-1-ene
4. 1-Bromo-2,2,3-trimethylbutane