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Benzene on reaction with HOCl in presenc...

Benzene on reaction with HOCl in presence of an acid produces organic compound (A). (A) on treatment with `NaNH_(2)//liq." "NH_(3)` furnishes another organic compound (B). (B) on treatment with `HBF_(4)` affords an organic compound (C) which on heating with `NaNO_(2)` gives organic compound (D). Identify (A), (B), (C) and (D).

Text Solution

AI Generated Solution

To solve the problem step by step, we will identify the organic compounds (A), (B), (C), and (D) produced in the reactions described. ### Step 1: Reaction of Benzene with HOCl in presence of an acid - **Reaction**: Benzene reacts with HOCl (Hypochlorous acid) in the presence of an acid (like HCl) to form chlorobenzene. - **Compound (A)**: The product formed is **Chlorobenzene (C6H5Cl)**. ### Step 2: Treatment of (A) with NaNH2 in liquid NH3 - **Reaction**: Chlorobenzene (A) reacts with sodium amide (NaNH2) in liquid ammonia (NH3). This reaction leads to the substitution of the chlorine atom with an amine group. ...
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An organic compound on treatment with Br_(2)//C Cl_(4) , gives a bromoderivative alkene. The compound will be

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Identity A,B,C……………(A,B…………. are all organic compound)

Identity A,B,C……………(A,B…………. are all organic compound)

Knowledge Check

  • An organic compound on treatment with Br_(2)//C Cl_(4) , gives a bromoderivative alkene. The compound will be

    A
    `CH_(3)CH=CH_(2)`
    B
    `CH_(3)CH=CHCH_(3)`
    C
    `HC-=CH`
    D
    `CH_(2)=CH_(2)`
  • Aniline is treated with bromine water to give an organic compound 'X' which when treated with NaNO_(2) and HCl at 0^(@)C gives a water soluble compound 'Y'. Compound 'Y' on treatment with CuCl_(2) and HCl gives compound Z. Compound Z is

    A
    o-bromochlorobenzene
    B
    p-bromochlorobenzene
    C
    2, 4, 6-tribromophenol
    D
    2, 4, 6-tribromochlorophenol
  • An organic compound 'A' on treatment with NH_(3) gives 'B', which on heating given 'C','C' when treated with Br_(2) in the presence of KOH produces ethylamine. Compound 'A' is

    A
    `CH_(3)-underset(CH_(3))underset(|)(CHCOOH)`
    B
    `CH_(3)CH_(2)COOH`
    C
    `CH_(3)COOH`
    D
    `CH_(3)CH_(2)CH_(2)COOH`