Silver chloride is prepared by
(i) dissolving 0.5 g of silver wire in nitric acid and adding excess of hydrochloric acid to silver nitrate formed. The silver chloride precipitated is separated, washed and dried. The weight of silver chloride is 0.66 g.
(ii) heating 1 g of silver metal in a current of dry chlorine gas till the metal is completely converted into its chloride. It is found to weight 1.32 g.
Illustrate the law of constant composition by the above data.

Explanation

To illustrate the law of constant composition using the given data about the preparation of silver chloride (AgCl), we will analyze the two methods of preparation and calculate the percentage composition of silver and chlorine in each case.

### Step 1: Analyze the first method of preparation
1. **Dissolve silver wire in nitric acid**:
- 0.5 g of silver (Ag) is dissolved in nitric acid to form silver nitrate (AgNO3).
2. **Add hydrochloric acid**:
- Excess hydrochloric acid is added to the silver nitrate, leading to the formation of silver chloride (AgCl).
3. **Weight of silver chloride formed**:
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