Home
Class 12
CHEMISTRY
Calculate the mass of sodium acetate (CH...

Calculate the mass of sodium acetate `(CH_(3)COONa)` required to make `500 mL` of `0.375` molar aqueous solution. Molar mass of sodium of acetate is `82.0245 g mol^(-1)`.

Text Solution

Verified by Experts

0.375 M aqueous solution means that 1000 mL of the solution contain sodium acetate = 0.375 mole
`therefore" 500 mL of the solution should contain sodium acetate"=(0.375)/(2)"mole"`
Molar mass of sodium acetate = `82.0245gmol^(-1)`
`therefore" Mass of sodium acetate acquired "=(0.375)/(2)" mole"xx"82.0245 g mol"^(-1)=15.380g.`
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • SOME BASIC CONCEPTS OF CHEMISTRY

    PRADEEP|Exercise NCERT (EXEMPLAR PROBLEMS WITH ANSWERS, HINTS AND SOLUTIONS) (NCERT EXEMPLAR PROBLEMS CHAPTER 1) SOME BASIC CONCEPTS OF CHEMISTRY (MULTIPLE CHOICE QUESTIONS - I)|15 Videos
  • SOME BASIC CONCEPTS OF CHEMISTRY

    PRADEEP|Exercise NCERT (EXEMPLAR PROBLEMS WITH ANSWERS, HINTS AND SOLUTIONS) (NCERT EXEMPLAR PROBLEMS CHAPTER 1) SOME BASIC CONCEPTS OF CHEMISTRY (MULTIPLE CHOICE QUESTIONS - II)|7 Videos
  • SOME BASIC CONCEPTS OF CHEMISTRY

    PRADEEP|Exercise CONCEPTUAL QUESTIONS|16 Videos
  • SOLUTIONS

    PRADEEP|Exercise IMPORTANT QUESTIONS FOR BOARD EXAMINATION|31 Videos
  • SURFACE CHEMISTRY

    PRADEEP|Exercise IMPORTANT QUESTIONS (FOR BOARD EXAMINATION)|28 Videos

Similar Questions

Explore conceptually related problems

Calculate the mass of sodium acetate (CH_(3)COONa) required to make 500 mL of 0.375 molar qqueous solution. Molar mass of sodium of acetate is 82.0245 g mol^(-1) .

How much mass of sodium acetate is required to make 250 mL of 0.575 molar aqueous solution?

Knowledge Check

  • Calculate the mass of sodium carbonate required to prepare 500 ml of a semi- normal solution

    A
    `13.25 g`
    B
    `26.5 g`
    C
    `53 g`
    D
    `6.125 g`
  • The amount of oxalic acid required to prepare 300 mL of 2.5 M solution is : (molar mass of oxalic acid = 90 g mol^(–1) ) :

    A
    67.5 g
    B
    9.45 g
    C
    6.75 g
    D
    94.5 g
  • What would be the molality of 20% (mass/mass) aqueous solution of KI ? (molar mass of KI = 166 g mol^(-1) )

    A
    `1.08`
    B
    `1.48`
    C
    `1.51`
    D
    `1.35`
  • Similar Questions

    Explore conceptually related problems

    Calculate the equivalent mass of the following: Sodium carbonate, if in 500 mL of 0.1 N solution, 2.65 g of sodium carbonate is present.

    Calculate the pH of 0.05 M sodium acetate solution of the pK_(a) of acetic acid is 4.74.

    Calculate the pH of 0.05M sodium acetate solution, if the pK_(a) of acetic acid is 4.74 .

    What would be the molality of 60% (mass/mass) aqueous solution of CH_(3)COOH ? (Molar mass of CH_(3)COOH = 60 g mol^(-1) )

    The hydrolysis constang of 0.1M aqueous solution of sodium acetate if K_(a) of CH_(3)COOH = 1.8 xx 10^(-5) is