Calculate the mass of sodium acetate `(CH_(3)COONa)` required to make `500 mL` of `0.375` molar aqueous solution. Molar mass of sodium of acetate is `82.0245 g mol^(-1)`.

Explanation

0.375 M aqueous solution means that 1000 mL of the solution contain sodium acetate = 0.375 mole
`therefore" 500 mL of the solution should contain sodium acetate"=(0.375)/(2)"mole"`
Molar mass of sodium acetate = `82.0245gmol^(-1)`
`therefore" Mass of sodium acetate acquired "=(0.375)/(2)" mole"xx"82.0245 g mol"^(-1)=15.380g.`