A welding fuel gas contains carbon and hydrogen only. Burning a small sample of it in oxygen gives 3.38 g carbon dioxide, 0.690 g of water and no other products. A volume of 10.0 L (measured at S.T.P.) of this welding gas is found to weigh 11.6 g. Calculate (i) empirical fomula (ii) molar mass of the gas, and (iii) molecular formula.

Explanation

To solve the problem step by step, we will follow these calculations:

### Step 1: Calculate the mass of carbon from the carbon dioxide produced.

Given:
- Mass of CO₂ produced = 3.38 g

The molar mass of CO₂ = 12 (C) + 16*2 (O) = 44 g/mol.
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