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A welding fuel gas contains carbon and h...

A welding fuel gas contains carbon and hydrogen only. Burning a small sample of it in oxygen gives 3.38 g carbon dioxide, 0.690 g of water and no other products. A volume of 10.0 L (measured at S.T.P.) of this welding gas is found to weigh 11.6 g. Calculate (i) empirical fomula (ii) molar mass of the gas, and (iii) molecular formula.

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To solve the problem step by step, we will follow these calculations: ### Step 1: Calculate the mass of carbon from the carbon dioxide produced. Given: - Mass of CO₂ produced = 3.38 g The molar mass of CO₂ = 12 (C) + 16*2 (O) = 44 g/mol. ...
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A welding fuel gas contains carbon and hydrogen only. Burning a small sample of it in oxygen gas 3.38 g carbon dioxide, 0.690 g of water and no other products. A volume of 10.0 L (measured at STP) of this welding gas is found to weigh 11.6 g. Calcuate

A welding fuel gas contains carbon and hydrogen only. Burning a small sample of it in oxygen gives 3.38 g carbon dioxide, 0.690 g of water and no other products. A volume of 10.0 litre (Measured at STP) of this welding gas is found weigh 11.6 g . Calculate (i) empirical formula, (ii) molar mass of the gas, and (iii) molecular formula.

Knowledge Check

  • A container contains 0.32g of O_(2) and the same volume of an unknown gas at the same T and P weighing 0.26g . If the gas obtain only C and H in the ratio 1 : 1 its molecular formula will be

    A
    `C_(4) H_(4)`
    B
    `C_(2) H_(2)`
    C
    `C_(6) H_(6)`
    D
    `C_(10) H_(10)`

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