The number of atoms present in one mole ...

The number of atoms present in one mole of an element is equal to Avogadro number. Which of the following element contains the greatest number of atom?

4g He

46g Na

0.40 g Ca

12g He

Text Solution

Verified by Experts

The correct Answer is:

`"4 g He"=(46)/(23)"mole = 1 mole"=N_(A)" atoms"`
`"46 g Na"=(46)/(23)"mole = 0.5 moles"=(N_(A))/(2)"atoms"`
`"0.40 g Ca"=(0.40)/(40)"mole"=10^(-2)" mole"=10^(-2)N_(A)" pr "(N_(A))/(100)" atoms"`
`"12 g He"=(12)/(4)" mole = 3 mole "=3N_(A)" atoms"`
Thus, 12 g He contains maximum number of atoms.

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The number of atoms present in one mole of an element is equal to Avogadro number. Which of the following elements contains the greatest number of atoms ?

4 g He

46 g Na

0.40 g Ca

12 g He

Which of the following contains the greatest number of oxygen atoms?

1 g of O

1 g of `O_(2)`

1 g of `O_(3)`

all have the same number of atoms

Which of the following contains the greatest number of atoms?

1.0 g of butane `(C_4 H_(10))`

1.0 g of nitrogen `(N_2)`

1.0 g of silver (Ag)

1.0 g of water `(H_2O)`