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20.0 mL of a mixture of oxygen (O(2)) an...

20.0 mL of a mixture of oxygen `(O_(2))` and ozone `(O_(3))` was heated till ozone was completely decomposed. The mixture of cooling was found to have a volume of 21 mL. Calculate the percentage of ozone by volume in the mixture.

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To solve the problem of calculating the percentage of ozone (O₃) in a mixture of oxygen (O₂) and ozone that was heated until the ozone was completely decomposed, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding the Reaction**: The decomposition of ozone can be represented by the following balanced chemical equation: \[ 2 \text{O}_3 \rightarrow 3 \text{O}_2 ...
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A 672 ml of a mixture of oxygen - ozone at N.T.P. were found to be weigh 1 gm. Calculate the volume of ozone in the mixture.

Knowledge Check

  • 30 ml of a mixture of oxygen (O_(2)) and ozone (O_(3)) was heated till ozone was completely decomposed. The mixture on cooling was found to expand 40 ml. The volume of O_(2) in original mixture was :

    A
    20 ml
    B
    10 ml
    C
    25 ml
    D
    15 ml

  • 1 g of a mixture of NaHCO_(3) and Na_(2)CO_(3) is heated to 150^(@)C . The volume of the CO_(2) produced at STP is 112.0 mL. Calculate the percentage of Na_(2)CO_(3) in the mixture (Na=23, C=12, O=16)

    A
    20
    B
    46
    C
    84
    D
    16

  • When 20ml of mixture of O_(2) and O_(3) is heated the volume becomes 29ml and disappears in alkaline pyragallol solution. What is the volume precent of O_(2) in the originl mixture ? .

    A
    `90%`
    B
    `10%`
    C
    `18%`
    D
    `2%`

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