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MnO(4)^(2-) undergoes disproportionation...

`MnO_(4)^(2-)` undergoes disproportionation reaction in acidic medium but `MnO_(4)^(-)` does not. Given reason.

Text Solution

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In `MnO_(4)^(-)` Mn is in the highest oxidation state of +7 and hence it can undergo disproportionation
In contrast the O.N of Mn in `MnO_(4)^(-)` is +6 therefore it can increase its O.N to +7 or decrease its cannot to some lower value thus `MnO_(4)^(2-)` undergoes disporportionation according to the following reactio
`3MnO_(4)^(2-)+4H^(+)rarr2MnO_(4)^(-)+MnO_(2)^(-)+2H_(2)O`
here the O.N of Mn increase from +6 in `MnO_(4)^(2-)` to +7 in `MnO_(4)^(-)` and decreases to +4 in `MnO_(2)` thus `MnO_(4)^(2-)` undergoes disproportionation in acidic medium
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MnO_(4)^(2-) underges disproportionation rection in acidic medium but MnO_(4)^(-) does not give reason

MnO_4^(2-) undergones disproportionation reaction in acidic medium but MnO_4^(-) does not . Give reason .

Knowledge Check

  • MnO_4^-2 undergoes disproportionation reaction in acidic medium but MnO_4^- does not because

    A
    In `MnO_4^-2`,Mn is in intermediate oxidation state
    B
    In `MnO_4^-2`,Mn is in lowest oxidation state
    C
    In `MnO_4^-2` ,Mn is in intermediate oxidation state
    D
    none of the above

  • In acidic medium, MnO_(4)^(2-)

    A
    disproportionates to `MnO_(2)`to `MnO_(4)^(-)`
    B
    is oxidized to `MnO_(4)^(-)`
    C
    is reduced to `MnO_(2)`
    D
    is reduced to `Mn^(2+)`

  • In acidic medium MnO_(4)^(2-)

    A
    Disproporationates to `MnO_(4)^(-) and MnO_(2)`
    B
    It oxidised to `MnO_(4)^(-)`
    C
    It reduced to `MnO_(2)`
    D
    It reduced to `Mn^(2+)`

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