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How many moles of electrons are involved...

How many moles of electrons are involved in the conversion of 1 mol `Cr_(2)O_(7)^(2-)` into `Cr^(3+)` ion?
`Cr_(2)O_(7)^(2-)+14H^(+)+6e^(-) to 2Cr^(3+)+7H_(2)O`

Text Solution

Verified by Experts

The correct Answer is:
6
The balanced equation is
`Cr_(2)O_(7)^(2-)+14H^(+)+6e^(-)rarr2Cr^(3+)+7H_(2)O`
thus 6 moles of electrons are needed in the abvoe conversion
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Knowledge Check

  • The charge required for the reduction of 1 mol Cr_(2)O_(7)^(2-) ions to Cr^(3+) is

    A
    `96500C`
    B
    `2xx96500C`
    C
    `3xx96500C`
    D
    `6xx96500C`

  • The charge required for the reduction of 1 mole of Cr_(2)O_(7)^(2-) ions to Cr^(3+) is

    A
    96500 C
    B
    `2xx96500 C`
    C
    `3 xx96500 C`
    D
    `6xx96500 C`

  • Number of electron involved in the reduction of Cr_(2)O_(7)^(2-) ion in acidic solution of Cr^(3+) is

    A
    4
    B
    6
    C
    3
    D
    4

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