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One mole of a gas expands with temperatu...

One mole of a gas expands with temperature T such thaht its volume, V=`KT^(2)`, where K is a constant. If the temperature of the gas changes by `60^(@)C` then the work done by the gas is `120R

A

R ln 60

B

kR In 60

C

60 kR

D

120R

Text Solution

Verified by Experts

The correct Answer is:
D
`V=kT^(2) therefore 2kT dT=dV`
and `P=(RT)/(V)=(RT)/(kT^(2))=(R)/(kT)`
`dW=PdV=2RdT, W=int PdV`
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