A copper ring having a cut such as not to from a complete loop is held horizontally and a bar magnet is dropped through the ring with its length along the axis of the ring. The acceleration of the falling magnet is

Options

A. `g`
B. `ltg`
C. ` gt g`
D. none

Explanation

To solve the problem, we need to analyze the situation step by step.

### Step 1: Understand the Setup
We have a copper ring that is not a complete loop (it has a cut) and is held horizontally. A bar magnet is dropped through the ring with its length aligned along the axis of the ring.

**Hint:** Visualize the setup and identify the key components: the incomplete copper ring and the falling bar magnet.

### Step 2: Analyze the Magnetic Field
When the bar magnet is dropped through the ring, it creates a changing magnetic field as it moves. According to Faraday's law of electromagnetic induction, a changing magnetic field through a loop induces an electromotive force (emf) in the loop.

**Hint:** Recall that a complete loop would allow for induced emf due to the changing magnetic flux.

### Step 3: Consider the Effect of the Cut in the Ring
Since the ring is not complete, it cannot sustain a continuous current. This means that even though the magnetic field is changing as the magnet falls, the incomplete ring will not generate a significant induced emf or current.

**Hint:** Think about how the cut in the ring affects the ability to generate a magnetic field through induced currents.

### Step 4: Determine the Acceleration of the Magnet
Because the incomplete ring does not generate a significant opposing magnetic field (due to the lack of induced current), the only force acting on the falling magnet is gravity. Therefore, the magnet will fall freely under the influence of gravity.

**Hint:** Remember that in free fall, the only acceleration acting on an object is due to gravity, which is approximately \( g = 9.81 \, \text{m/s}^2 \).

### Step 5: Conclude the Acceleration
Since the magnet falls under the influence of gravity without any opposing force from the ring, the acceleration of the falling magnet is equal to \( g \).

**Final Answer:** The acceleration of the falling magnet is \( g \).