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0.98g of the chloroplatinate salt of som...

`0.98g` of the chloroplatinate salt of some diaacidic base when ignited left `0.39g` of platinum as residue. What is the molecular mass of the base ? (At mass of `Pt = 195)` .

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Mass of the chloroplatinate salt `(W) = 0.98 g` Mass of platinum `(x) = 0.39g`
Acidity of the base `(n) = 2`
Now molar mass of the base `=(n)/(2)((Wxx195)/(x)-410)gmol^(-1)=(2)/(2)((0.98xx195)/(0.39)-410)gmol^(1)=80g//mol` .
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