A solution containing 12.0% sodium hydro...

A solution containing `12.0%` sodium hydroxide by mass has a density of `1.131 g//mL`. What volume of this solution contains `5.00 mol` of NaOH :

`0.0240 L`

`1.67 L`

`1.47 L`

`1.00 L`

Text Solution

Verified by Experts

The correct Answer is:

Molarity
`=((w//w)xxd xx10)/("Molar mass of solute")`
`=(12xx1.313xx10)/(40)`
`because("mol of solute")/("Vol") =(12xx1.131xx10)/(40)`
Vol `=1.47 L`

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