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Find the solubility product of a saturat...

Find the solubility product of a saturated solution of `Ag_(2)CrO_(4)` in water at `298K`, if the `EMF` of the cell `:`
`Ag|Ag^(o+)(satAg_(2)CrO_(4)sol)||Ag(0.1M)|Agis 0.164V` at `298K`.

Text Solution

Verified by Experts

The correct Answer is:
`K_(sp) = 2.287 xx 10^(-12)`
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Explore conceptually related problems

(A)Find the solubility product of a saturated solution of Ag_(2)CrO_(4) in water at 298 K if the emf of the cell Ag|Ag+ (saturated. Ag_(2)CrO_(4) solution) || Ag+ (0.1 M) | Ag is 0.164 V at 298 K. (B) What will be the resultant pH when 200 mL of an aqueous solution of HCl (pH = 2.0) is mixed with 300 mL of an aqueous of NaOH (pH = 12.0) ?

Find the solubility product of a saturated solution of Ag_2 CrO_4 in water at 298 K if the emf of the cell Ag| Ag^+ (satd. Ag_2CrO_4 soln.) || Ag^+ (0.1 M)| Ag is 0.164 V at 298 K.

Knowledge Check

  • The expression for the solubility product of Ag_(2)CrO_(3) will be

    A
    `K_(sp) = S^(2)`
    B
    `K_(sp) = 4S^(3)`
    C
    `K_(sp) = 27S^(4)`
    D
    `K_(sp) = S`
  • Which is the correct representation of the solubility product constant of Ag_(2)CrO_(4)

    A
    `[Ag^(+)]^(2)[CrO_(4)^(-2)]`
    B
    `[Ag^(+)] [CrO_(4)^(-2)]`
    C
    `[2Ag^(+)] [CrO_(4)^(-2)]`
    D
    `[2Ag^(+)]^(2) [CrO_(4)^(-2)]`
  • The e.f.m. of the cell Ag|Ag^(+)(0.1M)||Ag^(+)(1M)|Ag at 298K is

    A
    0.0059V
    B
    0.059V
    C
    5.9V
    D
    0.59V
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    Find the solubility product of a saturated solution product of a saturated of Ag_(2)CrO_(4) in water at 298K if the emf of the cell.

    Find the solution product of Ag_(2)CrO_(4) in water at 298 K if the e.m.f. of the cell Ag//Ag^(+) (saturated Ag_(2)CrO_(4)soln.)||Ag^(+)(0.1M)//Ag" is "0.164V" at "298K .

    The [Ag^(+)] ion in a saturated solution of Ag_(2)CrO_(4) at 25^(@)C is 1.5xx10^(-4)M . Determine K_(SP) of Ag_(2)CrO_(4) at 25^(@)C .

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