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Calculate the height to which water will...

Calculate the height to which water will rise in a capillary tube of diameter `1xx10^(-3)`m [given surface tension of water is `0.072Nm^(-1)` angle of contact is `0^(@),g=9.8ms^(-2)` and density of water `=1000kgm^(-3)`]

Text Solution

AI Generated Solution

To calculate the height to which water will rise in a capillary tube, we can use the formula for capillary rise: \[ h = \frac{2T \cos \theta}{r \rho g} \] Where: - \( h \) = height of the liquid column in the capillary tube ...
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Knowledge Check

  • Water rises in a capillary tube of diameter 0.2xx10^(2)m upto a height of 1.5 cm. The surface tension of water is-

    A
    `73.5xx10^(1)N//m`
    B
    `73.5xx10^(-3)dy"ne"//cm`
    C
    `35.7xx10^(-3)N//m`
    D
    `43.5xx10^(-3)`
  • The surface tension of water is 0.072 N/m. The height to which water will rise in a capillary tube of bore diameter 0.048 cm will be (Angle of contact of water is zero , acceleration due to gravity is 10 m//s^2 and density of water =1000 kg//m^3 ).

    A
    6 cm
    B
    8 cm
    C
    4 cm
    D
    10 cm
  • A capillary tube of 2mm diameter. What is the height to which water rises, if surface tension of water is 7.4 xx 10^(-9) Nm^(-1) and angle of contact is 0^(@) ?

    A
    0.25mm
    B
    1.51mm
    C
    0.4mm
    D
    0.5mm
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    Water rises in a capillary tube to a height of 10 cm . If surface tension of water is 9.8 xx 10^(-2) "Nm"^(-1) . Then find out the radius of the capillary tube. Given g=9.8 "ms"^(-2) and density of water = 10^(3) "kgm"^(-3).

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    If the surface tension of water is 0.06 Nm^(-1) , then then the capillary rise in a tube of diameter 1 mm is (theta=0^(@))