Home
Class 12
PHYSICS
In the given figure L=1 metre if total g...


In the given figure `L=1` metre if total gravitational force on 4 kg mass is `verF_(1)` and on 2 kg mass is `vecF_(2)` then find out the ratio of `|(vecF_(2))/(vecF_(2))|`

Text Solution

Verified by Experts

The correct Answer is:
`sqrt(2)`

`F_(1)=|F_(42)+vecF_(41)+vecF_(41)|`
`=(G8)/(4L^(2))+(G4)/(2L^(2))(2cos45)=((2+2sqrt(2))G)/(L^(2))`
`F_(2)=|vecF_(24)+vecF_(21)+vecF_(21)|=(G8)/(4L^(2))+(G2)/(2L^(2))(2cos45)`
`=(G)/(L^(2))(2+sqrt(2))implies(F_(1))/(F_(2))=sqrt(2)`
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • GRAVITATION

    ALLEN|Exercise Exercise 4 B (Brain Storming Subjective Exercise)|20 Videos
  • GRAVITATION

    ALLEN|Exercise Exercise 5 A (Previous Year Questions)|26 Videos
  • GRAVITATION

    ALLEN|Exercise Exercise 3 (Miscellaneous Type Questions)|20 Videos
  • GEOMETRICAL OPTICS

    ALLEN|Exercise subjective|14 Videos
  • KINEMATICS-2D

    ALLEN|Exercise Exercise (O-2)|48 Videos

Similar Questions

Explore conceptually related problems

In the given figure, find the force acting on a particle of mass 1 kg.

Two particle of mass 4 kg & 2kg are located as shown in figure then find out the position of centre of mass.

Knowledge Check

  • Two forces vecF_(1) and vecF_(2) are acting at right angles to each other, find their resultant ?

    A
    `sqrt(F_(1)^(2)+F_(2)^(2))`
    B
    `sqrt(F_(1)^(2)-F_(2)^(2))`
    C
    `F_(1)+F_(2)`
    D
    `F_(1)-F_(2)`
  • In the given figure tension at the mid-point of string -2 . If mass of string -1 is 6 kg and mass of string -2 is 4 kg .

    A
    `70 N`
    B
    `60 N`
    C
    `80 N`
    D
    `50 N`
  • Which of the four arrangements in the figure correctly shows the vector addition of two forces vecF_(1) and vecF_(2) to yield the third force vecF_(3)

    A
    B
    C
    D
  • Similar Questions

    Explore conceptually related problems

    Two particles of mass m_(1) "and" m_(2) are in space at separation vecr [vector from m(1) to m_(2) ]. The only force that the two particles experience is the mutual gravitational pull. The force applied by m_(1) "on" m_(2) "is" vecF . Prove that mu(d^(2)vecr)/(dt^(2)) = vecF where mu"(m_(1)m_(2))/(m_(1) + m_(2)) is known as reduced mass for the two particle system .

    If the four forces as shown are in equilibrium Express vecF_(1) & vecF_(2) in unit vector form.

    At a picnic, there is a contest in which hoses are used to shoot water at a beach ball from three directions. As a result, three forces act on the ball, vecF_(1), vecF_(2) and vecF_(3) (see the drawing). The magnitudes of vecF_(1) and vecF_(2)= 50. 0N and F_(2) = 90. 0N. Using the graphical technique, determine the angle such that the resultant force acting on the ball is zero.

    The gravitational force between two stones of mass 1 kg each separated by a distance of 1 metre in vacuum is

    A body is at rest under the action of three forces, two of which are vecF_(1)=4hati, vecF_(2)=6hatj , the third force is