Two slits at a distance of `1mm` are illuminated by a light of wavelength `6.5xx10^-7m`. The interference fringes are observed on a screen placed at a distance of `1m`. The distance between third dark fringe and fifth bright fringe will be
A
0.65 mm
B
1.625 mm
C
3.25 mm
D
0.975 mm
Text Solution
Verified by Experts
The correct Answer is:
B
Distance between third dark fringe and the fifth bright fringe. `=2.5beta=2.5(lamdaD)/(d)=2.5(6.5xx10^(-7)xx1)/(10^(-3))=1.625mm`
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