Home
Class 12
PHYSICS
A particle moves in x-y plane according ...

A particle moves in `x-y` plane according to the law `x = 4 sin 6t and y = 4 (1-cos 6t)`. The distance traversed by the particle in 4 second is (`x & y` are in meters)

A

`96m`

B

`45m`

C

`24m`

D

`108m`

Text Solution

Verified by Experts

The correct Answer is:
A
A particle ……………
Distance `= sqrt((dx)^(2)+(dy)^(2))`
`= sqrt(((dx)/(dt))^(2)+((dy)/(dt))^(2))dt`
`= sqrt((24sin6t)^(2)+(24cos6t)^(2))dt = 24int_(0)^(4)dt = 96 m`
Promotional Banner

Similar Questions

Explore conceptually related problems

A particle moves in y plane according to the law x=4sin6t and y=4(1-cot6t) .The distance traversed by the particle in 4 seconds (in meter) s (x and y are in

A point moves in x-y plane according to the law x= 4 sin 6 t and y= 4 ( 1- cos 6 t) . Fimd distance traversed by the particle in 5 seconds , when (x0 and (y) are in metres.

A particle moves in xy plane accordin to the law x=a sin w t and y=a (1- cos w t ) where a and w are costant . The particle traces.

A particle moves in x-y plane according to ru le x =a sin omegat and y= a cos omegat . The particles follows:

A particle moves in x-y plane according to rule x=asin omegat and y=-acosomegat . The particle follows

A particle moves in xy plane according to the law x = a sin omegat and y = a(1 – cos omega t) where a and omega are constants. The particle traces

A particule moves in x - y plane acording to rule x = a sin omega t and y = a cos omega t . The particle follows