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A particle moves in x-y plane according ...

A particle moves in `x-y` plane according to the law `x = 4 sin 6t and y = 4 (1-cos 6t)`. The distance traversed by the particle in 4 second is (`x & y` are in meters)

A

`96m`

B

`45m`

C

`24m`

D

`108m`

Text Solution

Verified by Experts

The correct Answer is:
A
A particle ……………
Distance `= sqrt((dx)^(2)+(dy)^(2))`
`= sqrt(((dx)/(dt))^(2)+((dy)/(dt))^(2))dt`
`= sqrt((24sin6t)^(2)+(24cos6t)^(2))dt = 24int_(0)^(4)dt = 96 m`
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Knowledge Check

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