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The average rotational kinetic energy of...

The average rotational kinetic energy of hydrogen molecule at a temperature `T` is `E`. The average translational kinetic energy of helium at same temperature will be:

A

`(2E)/(3)`

B

`(5E)/(3)`

C

`E`

D

`(3E)/(2)`

Text Solution

Verified by Experts

The correct Answer is:
D

Law of equipartition of energy
`lt KE_(R)gt = 2.(1)/(2)kT = E`
`:. ltKE_(T)gt = 3. (1)/(2)kT`
`ltKE_(T)gt = (3E)/(2)`
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