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One mole of an ideal gas undergoes a pro...

One mole of an ideal gas undergoes a process
`P=P_(0)-alphaV^(2)`
where `alpha` and `P_(0)` are positive constant and V is the volume of one mole of gas
Q. When temperature is maximum, volume is

A

`sqrt((P_(0))/(3alpha))`

B

`sqrt((P_(0))/(alpha))`

C

`sqrt((P_(0))/(2alpha))`

D

`sqrt(P_(0)alpha)`

Text Solution

Verified by Experts

The correct Answer is:
A
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Knowledge Check

  • One mole of an ideal gas undergoes a process P=P_(0)-alphaV^(2) where alpha and P_(0) are positive constant and V is the volume of one mole of gas Q. When temperature is maximum, pressure is

    A
    `(2)/(3)P_(0)`
    B
    `P_0`
    C
    `(P_(0))/(3)`
    D
    `(3)/(2)P_(0)`

  • One mole of an ideal gas undergoes a process P=P_(0)-alphaV^(2) where alpha and P_(0) are positive constant and V is the volume of one mole of gas Q. The maximum attainable temperature is

    A
    `(P_(0))/(R)sqrt((P_(0))/(3alpha))`
    B
    `(2)/(3)(P_(0))/(R)sqrt((P_(0))/(3alpha))`
    C
    `sqrt((P_(0))/(3alpha))`
    D
    `sqrt((P_(0))/(R))`

  • One mole of an ideal gas undergoes a process in which T = T_(0) + aV^(3) , where T_(0) and a are positive constants and V is molar volume. The volume for which pressure with be minimum is

    A
    `((T_(0))/(2a))^(1//3)`
    B
    `((T_(0))/(3a))^(1//3)`
    C
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    D
    `(a)/(3T_(0))^(2//3)`

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