Calculate the magnitude and direction of the electric field at a point P which is 30 cm to the right of a point charge `Q = -3.0 xx 10^(-6) C `

Explanation

To calculate the magnitude and direction of the electric field at point P, which is 30 cm to the right of a point charge \( Q = -3.0 \times 10^{-6} \, \text{C} \), we can follow these steps:

### Step 1: Identify the Charge and its Position
We have a point charge \( Q = -3.0 \times 10^{-6} \, \text{C} \) located at a certain point. Point P is located 30 cm (or 0.3 m) to the right of this charge.

### Step 2: Determine the Direction of the Electric Field
Since the charge is negative, the electric field lines will point towards the charge. Therefore, at point P, which is to the right of the charge, the electric field will be directed to the left.

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