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If in a DeltaABC ,a sin A=b sin B, then ...

If in a `DeltaABC` ,a sin A=b sin B, then the triangle, is

A

right angled

B

equilaterial

C

isosceles

D

none of these

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze the given condition in triangle \( \Delta ABC \): \( A \sin A = B \sin B \). ### Step-by-step Solution: 1. **Understand the Given Condition**: We start with the equation \( A \sin A = B \sin B \). This implies a relationship between the sides \( A \) and \( B \) of triangle \( ABC \). **Hint**: Recall the sine rule, which relates the sides of a triangle to the sines of its angles. 2. **Use the Sine Rule**: According to the sine rule, we have: \[ \frac{A}{\sin A} = \frac{B}{\sin B} = \frac{C}{\sin C} = k \] where \( k \) is a constant. **Hint**: This means that each side divided by the sine of its opposite angle is equal to a constant. 3. **Express \( A \sin A \) and \( B \sin B \)**: From the sine rule, we can express \( A \) and \( B \) in terms of \( k \): \[ A = k \sin A \quad \text{and} \quad B = k \sin B \] **Hint**: Substitute these expressions back into the original equation. 4. **Substituting into the Equation**: Substitute \( A \) and \( B \) into the equation \( A \sin A = B \sin B \): \[ (k \sin A) \sin A = (k \sin B) \sin B \] This simplifies to: \[ k \sin^2 A = k \sin^2 B \] **Hint**: Since \( k \) is not zero (as it represents a ratio of sides), we can divide both sides by \( k \). 5. **Canceling \( k \)**: Dividing both sides by \( k \) gives us: \[ \sin^2 A = \sin^2 B \] **Hint**: Recall the properties of sine functions and their implications on angles. 6. **Conclusion about Angles**: From \( \sin^2 A = \sin^2 B \), we conclude that: \[ \sin A = \sin B \quad \text{or} \quad \sin A = -\sin B \] Since angles in a triangle cannot be negative, we have: \[ A = B \] **Hint**: If two angles in a triangle are equal, then the sides opposite those angles are also equal. 7. **Final Result**: Since \( A = B \), it follows that the triangle \( \Delta ABC \) is an isosceles triangle. **Hint**: An isosceles triangle has at least two equal sides. ### Final Answer: The triangle \( \Delta ABC \) is an **isosceles triangle**.
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Knowledge Check

  • If in a Delta ABC, cos B = (sin A)/(2 sin C), then the triangle is

    A
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    B
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    D
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    B
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    C
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    D
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