Home
Class 11
PHYSICS
Two men of masses m and m//2 starts clim...

Two men of masses `m` and `m//2` starts climbing up on two masseless strings fixed at the ceiling with acceleration `g` and `g//2` respectively. The ratio of tensions in the two strings will be `:`

A

`2:1`

B

`4:1`

C

`4:3`

D

`8:3`

Text Solution

Verified by Experts

The correct Answer is:
D
FBD of man of mass `(m)`

`T_(1)=mg+mg`
`T_(1)=2mg`
`rArr T_(1):T_(2): : 8:3`
FBD of man of mass `(m//2)`

`T_(2)=(m)/(2)g+(m)/(2).(g)/(2)`
`T_(2)=(mg)/(2)[(3)/(2)]=(3mg)/(4)`
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • DAILY PRACTICE PROBLEMS

    RESONANCE|Exercise dpp 27|3 Videos

  • DAILY PRACTICE PROBLEMS

    RESONANCE|Exercise dpp 28|7 Videos

  • DAILY PRACTICE PROBLEMS

    RESONANCE|Exercise dpp 25|5 Videos

  • CURRENT ELECTRICITY

    RESONANCE|Exercise Exercise|54 Videos

  • ELASTICITY AND VISCOCITY

    RESONANCE|Exercise Advanced Level Problems|9 Videos

Similar Questions

Explore conceptually related problems

A mass of 1kg attached to one end of a string is first lifted up with an acceleration 4.9m//s^(2) and then lowered with same acceleration What is the ratio of tension in string in two cases .

A body of mass M is hanging by an inextensible string of mass m. If the free end of the string accelerates up with constant acceleration a. find the variation of tension in the string a fuction of the distance measured from the mass M (bottom of the string).

Knowledge Check

  • A uniform rod of mass m and length L is suspended with two massless strings as shown in figure. If the rod is at rest in a horizontal position the ratio of tension in the two strings T_(1)//T_(2) is

    A
    `1:1`
    B
    `1:2`
    C
    `2:1`
    D
    `4:3`

  • A uniform rod of mass m and length L is suspended with two massless strings as shown in the figure. If the rod is at rest in a horizontal position the ratio of tension in the two strings T_1/T_2 is:

    A
    `1:1`
    B
    `1:2`
    C
    `2:1`
    D
    `4:3`

  • A mass M is lowered with the help of a string by a distance h at a distance acceleration g//2 . The work done by the string will be

    A
    (a) `(Mgh)/(2)`
    B
    (b) `-(Mgh)/(2)`
    C
    (c) `(3Mgh)/(2)`
    D
    (d) `-(3Mgh)/(2)`

    • Similar Questions

    Explore conceptually related problems

    In the above example, if two blocks have masses 1kg and 2kg respectively then find their acceleration and tension in different string.

    A mass "M" is lowered with the help of a string by a distance "h" at a constant acceleration (g)/(2) .The work done by the string will be

    A mass M is lowered with the help of a string by a distance h at a constant acceleration g//2 .The work done by the string will be :

    A string is used to pull a block of mass m vertically up by a distance h at a constant acceleration (g)/(3) . The work done by the tension in the string is

    Two objects A and B of masses m_(A) and m_(B) are attached by strings as shown in fig. If they are given upward acceleration then the rato of tension T_(1) : T_(2) is-

    Home
    Profile