If `x!=1\ a n d\ f(x)=(x+1)/(x-1)` is a real function, then `f(f(f(2)))` is (a) `1` (b) `2` (c) `3` (d) 4

Explanation

To solve the problem of finding \( f(f(f(2))) \) where \( f(x) = \frac{x+1}{x-1} \) and \( x \neq 1 \), we will proceed step by step.

### Step 1: Calculate \( f(2) \)
We start by substituting \( x = 2 \) into the function \( f(x) \).

\[ f(2) = \frac{2 + 1}{2 - 1} = \frac{3}{1} = 3 \]
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