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Using binomial theorem compute : (99)^5...

Using binomial theorem compute : `(99)^5`

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`(99)^{5}=(100-1)^{5}`
`=5_{C_0}(100)^{5}-5_{C_1}(100)^{4}(1)+5_{C_2}(100)^{3}(1)^{2}-5_{C_3}(100)^{2}(1)^{3}+5_{C_4}(100)(1)^{4}-5_{C_5}(1)^{5}`
`=(100)^{5}-5(100)^{4}+10(100)^{3}-10(100)^{2}+5(100)-1`
`=10000000000-500000000+10000000-100000+500-1`
`=10010000500-500100001`
`=9509900499`
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RD SHARMA-BINOMIAL THEOREM-Solved Examples And Exercises
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