A body of mass 10 kg lies on a rough horizontal surface. When a horizontal force of F newtons acts on it, it gets an acceleration of `5 m//s^(2)`. And when the horizontal force is doubled, it gets an acceleration of `18 m//s^(2)`. The coefficient of friction between the body and the horizontal surface is

Options

A. 0.2
B. 0.4
C. 0.6
D. 0.8

Explanation

To solve the problem step by step, we will analyze the forces acting on the body and apply Newton's second law of motion.

### Step 1: Identify the forces acting on the body
The body has a mass \( m = 10 \, \text{kg} \) and is subjected to a horizontal force \( F \). The frictional force \( F_{\text{friction}} \) opposes the motion. The normal force \( N \) acting on the body is equal to its weight, which is given by:
\[ N = mg = 10 \, \text{kg} \times 9.8 \, \text{m/s}^2 = 98 \, \text{N} \]
The frictional force can be expressed as:
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