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The linear charge density on a ring of r...

The linear charge density on a ring of radius R is `lambda=lambda_0 sin (theta)` where `lambda_0` is a constant and `theta` is angle of radius vector of any point on the ring with x-axis. The electric potential at centre of ring is

A

0

B

`(lambda_(0))/(in_(0))`

C

`(lambda_(0))/(piin_(0))`

D

`(lambda_(0))/(2pi in_(0))`

Text Solution

Verified by Experts

The correct Answer is:
A
All the charges are at a distance R.
`:. V=(kq_("net"))/R=0`
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Knowledge Check

  • The linear charge density on a dielectric ring of radius R vanes with theta as lambda = lambda_0 cos theta//2 , where lambda_0 is constant. Find the potential at the center O of the ring [in volt].

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  • A charge Q is uniformly distributed only on the fourths portion of a ring of radius R . The elctric potential at centre of ring is

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