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The set of points where the function ...

The set of points where the function `f(x)` given by `f(x)=|x-3|cosx` is differentiable, is `R` (b) `R-{3}` (c) `(0,\ oo)` (d) none of these

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AI Generated Solution

To determine the set of points where the function \( f(x) = |x - 3| \cos x \) is differentiable, we need to analyze the function, particularly at the point where the modulus function could cause non-differentiability. ### Step-by-step Solution: 1. **Identify the critical point**: The function \( f(x) \) contains the absolute value \( |x - 3| \). The expression inside the absolute value becomes zero when \( x = 3 \). Therefore, \( x = 3 \) is a critical point where we need to check for differentiability. **Hint**: Check where the expression inside the absolute value equals zero to find critical points. ...
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Knowledge Check

  • The set of points where the function f(x)=x|x| is differentiable is:

    A
    `(-oo,oo)`
    B
    `(-oo,0)uu(0,oo)`
    C
    `(0,oo)`
    D
    `[0,oo]`
  • The set of points where the function f(x) = x[x] is differentiable is

    A
    `(-infty, infty)`
    B
    `(-infty, 0) cup [0,infty)`
    C
    `(0,infty)`
    D
    `[0,infty)`
  • The set of points, where the function f (x ) = x |x | is differentiable, is

    A
    `(-oo,oo)`
    B
    `(-oo , 0) cup ( 0,oo) `
    C
    `(o ,oo)`
    D
    `[0, oo) `
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    The set of points where the function f(x)=x|x| is differentiable is (a)(-oo,oo) (b) (-oo,0)uu(0,oo)(c)(0,oo)(d)[0,oo]

    The set of points where the function f(x)=x|x| is differentiable is (-oo,oo)(b)(-oo,0)uu(0,oo)(0,oo)(d)[0,oo)