On crossing two heterozygous tall plants (Tt), a total of 500 plants were obtained in `F_(1)` generation. What will be the respective number of tall and dwarf plants obtained of `F_(1)` generation ?

Options

A. `375,125`
B. `250,250`
C. `475,25`
D. `350,150`

Explanation

To solve the problem of determining the number of tall and dwarf plants in the F1 generation from the cross of two heterozygous tall plants (Tt), we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Genotype of Parents**:
- The parents are both heterozygous tall plants, represented as Tt. This means they have one dominant allele (T) for tallness and one recessive allele (t) for dwarfness.

2. **Determine the Possible Gametes**:
- Each parent can produce two types of gametes: T (tall) and t (dwarf).

3. **Set Up a Punnett Square**:
- Create a Punnett square to visualize the possible combinations of alleles from the two parents:
```
T t
------------
T | TT | Tt |
------------
t | Tt | tt |
------------
```
- From the Punnett square, we can see the possible genotypes of the offspring:
- TT (homozygous tall)
- Tt (heterozygous tall)
- Tt (heterozygous tall)
- tt (homozygous dwarf)

4. **Count the Genotypes**:
- The genotypic ratio from the Punnett square is:
- 1 TT : 2 Tt : 1 tt
- This means:
- 3 plants are tall (TT + Tt + Tt)
- 1 plant is dwarf (tt)

5. **Calculate the Phenotypic Ratio**:
- The phenotypic ratio of tall to dwarf plants is 3:1.

6. **Calculate the Total Number of Plants**:
- According to the problem, there are a total of 500 plants in the F1 generation.

7. **Calculate the Number of Tall and Dwarf Plants**:
- To find the number of tall plants:
- Tall plants = (3/4) * 500 = 375
- To find the number of dwarf plants:
- Dwarf plants = (1/4) * 500 = 125

8. **Final Answer**:
- Therefore, the respective number of tall and dwarf plants in the F1 generation is:
- Tall plants: 375
- Dwarf plants: 125