Number of electron having `l+m` value equal to zero in `._(26)Fe` may be

Options

A. 13
B. 20
C. 7
D. 12

Answer

1

Explanation

`._(26)Fe-1s^(2),2s^(2)2p^(6),3s^(2)3p^(6),3d^(6),4s^(2)`
`l+m=0" "rArr" "l=0,m=0" "i.e" "s-`subshell
`l=1,m=-1" "i.e." "` one orbital of `p.`
`l=2,m=2" "i.e." "` one of `d-` orbitals
hence there are 12 or 14 electron as in `d-` orbital it may be one or two electron having `m=-2`