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How much energy will be needed for a bod...

How much energy will be needed for a body of mass 100kg to escape from the earth- `(G = 10M//S^(2)` and radius of earth = 6.4 xx 10^(6) m)`

A

`6.4 xx 10^(9)` joule

B

`8 xx 10^(6)` jule

C

`4 xx 10^(16)` jule

D

zero

Text Solution

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The correct Answer is:
To find the energy needed for a body of mass 100 kg to escape from the Earth, we can use the concept of gravitational potential energy and escape velocity. The energy required for a body to escape the gravitational pull of the Earth can be calculated using the formula: \[ E = mgh \] However, in this case, we can also use the escape velocity formula to determine the kinetic energy required for escape. ### Step-by-Step Solution: 1. **Identify the given values:** - Mass of the body, \( m = 100 \, \text{kg} \) - Acceleration due to gravity, \( g = 10 \, \text{m/s}^2 \) - Radius of the Earth, \( r = 6.4 \times 10^6 \, \text{m} \) 2. **Calculate the escape velocity (v):** The escape velocity from the surface of the Earth is given by the formula: \[ v = \sqrt{2gr} \] Substituting the values: \[ v = \sqrt{2 \times 10 \, \text{m/s}^2 \times 6.4 \times 10^6 \, \text{m}} \] 3. **Calculate the value inside the square root:** \[ 2gr = 2 \times 10 \times 6.4 \times 10^6 = 128 \times 10^6 = 1.28 \times 10^8 \] 4. **Calculate the escape velocity:** \[ v = \sqrt{1.28 \times 10^8} = 1.13 \times 10^4 \, \text{m/s} \] 5. **Calculate the kinetic energy (KE) required for escape:** The kinetic energy required to reach this escape velocity is given by: \[ KE = \frac{1}{2} mv^2 \] Substituting the values: \[ KE = \frac{1}{2} \times 100 \, \text{kg} \times (1.13 \times 10^4 \, \text{m/s})^2 \] 6. **Calculate \( (1.13 \times 10^4)^2 \):** \[ (1.13 \times 10^4)^2 = 1.2769 \times 10^8 \] 7. **Calculate the kinetic energy:** \[ KE = \frac{1}{2} \times 100 \times 1.2769 \times 10^8 = 6.3845 \times 10^9 \, \text{J} \] 8. **Final result:** Rounding off, the energy needed for the body to escape from the Earth is approximately: \[ KE \approx 6.4 \times 10^9 \, \text{J} \] ### Conclusion: The energy required for a body of mass 100 kg to escape from the Earth is approximately \( 6.4 \times 10^9 \, \text{J} \). ---
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If a spaceship orbits the earth at a height of 500 km from its surface, then determine its (i) kinetic energy, (ii) potential energy, and (iii) total energy (iv) binding energy. Mass of the satellite = 300 kg, Mass of the earth = 6xx10^(24) kg , radius of the earth = 6.4 xx 10^(6) m, G=6.67 xx 10^(-11) "N-m"^(2) kg^(-2) . Will your answer alter if the earth were to shrink suddenly to half its size ?

Knowledge Check

  • How much energy will be necessary for making a body of 500 kg escape from the earth [g=9.8 ms^(2)," radius of earth "=6.4xx10^(6)m]

    A
    About `9.8xx10^(6) J`
    B
    About `6.4xx10^(8) J`
    C
    About `3.1xx10^(10) J`
    D
    About `27.4xx10^(22) J`
  • The energy required for a body of mass 1000 kg to escape from the attraction of the earth is (If radius of the earth is 6400 km and g=10m//s^(2) )

    A
    `64xx10^(7)J`
    B
    `64xx10^(8)J`
    C
    `64xx10^(9)J`
    D
    `6400J`
  • How much energy should be supplied to a body of mass 500kg, so that it can escape from the gravitational pull of the earth? [g=10 m//s^(2) and R=6400 km]

    A
    `6.4xx10^(10)J`
    B
    `3.2xx10^(10)J`
    C
    `6.4xx10^(8)J`
    D
    `3.2xx10^(6)J`
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    Calculate (i) kinetic energy (ii) potential energy and (iii) total energy of a satellite of mass 200 kg orbiting around the earth in an orbit of height 100 km from the surface of earth. Given, mass of earth = 10^(25) kg ,radius of earth = 6.4 xx 10^(6) m, G = 6.67 xx 10^(-11) Nm^(2) kg^(-2) .

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