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In the expansion of (a^(1/3)+b^(1/9))^65...

In the expansion of `(a^(1/3)+b^(1/9))^6561`, where `'a' and 'b'` are distinct prime numbers, then the number of irrational terms are

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In the expansion of (7^(1//3)+11^(1//9))^(6561) ,

In the expansion of (7^(1//3)+11^(1//9))^(6561) ,

Knowledge Check

  • In the expansion of (5^(1//6)+ 2^(1//8))^(100) , the number of irrational terms are

    A
    93
    B
    95
    C
    97
    D
    99

  • If tan {cos^(-1)((4)/(5))+tan^(-1)((2)/(3))}=(a)/(b) , where a and b are co-prime natural numbers, then:

    A
    `a+b=23`
    B
    `a-b=12`
    C
    `3b=a+2`
    D
    `2a=3b`

    • Similar Questions

    Explore conceptually related problems

    In the expansion of (7^(1//3)+11^(1//9))^(6561) , (a)there are exactly 730 rational term (b)there are exactly 5831 irrational terms (c)the term which involves greatest binomial coefficients is irrational (d)the term which involves greatest binomial coefficients is rational

    In the expansion of (7^(1/3)+11^(1/9))^(6561) (a)there are exactly 730 rational term (bthere are exactly 5831 irrational term (bthe term which involves greatest binomial coefficients is irrational (d)the term which involves greatest binomial coefficients is rational

    In the expansion of (7^(1/3)+11^(1/9))^(6561) , the number of terms free from radicals is:

    In the expansion of (7^(1/3)+11^(1/9))^(6561) , the number of terms free from radicals is:

    In the expansion of (7^((1)/(3))+11^((1)/(9)))^(6561), the number of terms free from radicals is:

    In the expansion of (7^((1)/(3))+11^((1)/(9)))^(6561), the number of terms free from radicals is:

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