Write the net ionic equation for the rection of potassium dichromate (VI) `K_(2)Cr_(2)O_(7)` with sodium suphite `Na_(2)SO_(3)` in acid solution to give chromium (III) ion and suphate ion

Explanation

To write the net ionic equation for the reaction of potassium dichromate (VI) \( K_2Cr_2O_7 \) with sodium sulfite \( Na_2SO_3 \) in an acidic solution, we need to follow these steps:

### Step 1: Write the balanced molecular equation
The first step is to identify the reactants and products. The reaction involves potassium dichromate, sodium sulfite, and an acid (which we will assume is hydrochloric acid, \( HCl \), for this example). The products are chromium (III) ions \( Cr^{3+} \) and sulfate ions \( SO_4^{2-} \).

The balanced molecular equation is:
\[
K_2Cr_2O_7 + 3Na_2SO_3 + 8HCl \rightarrow 2CrCl_3 + 3Na_2SO_4 + 4H_2O
...