Given standard electrode potentials
`K^(o+)|K=-2.93V, Ag^(o+)|Ag=0.80V`,
`Hg^(2+)|Hg=0.79V`
`Mg^(2+)|Mg=-2.37V,Cr^(3)|Cr=-0.74V`
Arrange these metals in their increasing order of reducing power.

Explanation

Lower the electrode potential better is the reducing agent since the electrode potential increase in the order `K^(+)//K(-2.93 V)Mg^(2+)//Mg(-2.37 V),Cr^(3+)//Cr(-074 V),F^(2+)//Hg(0.79V ),Ag^(+)//Ag(0.80 V)` therefore oreducing power of metals decrases in the same order i.e k, Mg , Cr Hg ,Ag