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Consider the titraton of potassium dich...

Consider the titraton of potassium dichromate solution with acidfied mohr salt solution using dmiethylamine as incdicator the number of moles of mohr salt required per mole of dichromate

A

3

B

4

C

5

D

6

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The correct Answer is:
To solve the problem of determining the number of moles of Mohr's salt (FeSO4(NH4)2SO4·6H2O) required per mole of potassium dichromate (K2Cr2O7) in an acidified titration, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Reaction**: The reaction between potassium dichromate and Mohr's salt in acidic medium can be represented as: \[ K_2Cr_2O_7 + 6FeSO_4 + 7H_2SO_4 \rightarrow K_2SO_4 + Cr_2(SO_4)_3 + 3Fe_2(SO_4)_3 + 7H_2O \] 2. **Determine Oxidation States**: - In K2Cr2O7, chromium (Cr) is in the +6 oxidation state. - In FeSO4, iron (Fe) is in the +2 oxidation state. - In the products, Cr is reduced to the +3 oxidation state, and Fe is oxidized to the +3 oxidation state. 3. **Balance the Reaction**: From the balanced equation, we see that: - 1 mole of K2Cr2O7 reacts with 6 moles of FeSO4. - This indicates that for every mole of dichromate, 6 moles of Mohr's salt are required. 4. **Conclusion**: Therefore, the number of moles of Mohr's salt required per mole of potassium dichromate is 6. ### Final Answer: The number of moles of Mohr's salt required per mole of potassium dichromate is **6**. ---

To solve the problem of determining the number of moles of Mohr's salt (FeSO4(NH4)2SO4·6H2O) required per mole of potassium dichromate (K2Cr2O7) in an acidified titration, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Reaction**: The reaction between potassium dichromate and Mohr's salt in acidic medium can be represented as: \[ K_2Cr_2O_7 + 6FeSO_4 + 7H_2SO_4 \rightarrow K_2SO_4 + Cr_2(SO_4)_3 + 3Fe_2(SO_4)_3 + 7H_2O ...
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