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A list of species having the formula of `XZ_(4)` is given below `XeF_(4), SF_(4), SiF_(4), BF_(4)^(-), BrF_(4)^(-), [Cu(NH_(3))4]^(2+),[FeCl_(4)]^(2-), [CoCl_(4)]^(2-)` and `[PtCl_(4)]^(2-)`
Defining shape on the basis of the locatiion of `X` and `Z` atoms, the total number of species having a square planar shape is

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To determine the total number of species having a square planar shape from the given list of compounds with the formula XZ₄, we will analyze each compound step by step. ### Step-by-Step Solution: 1. **Identify the Compounds**: The given compounds are: - XeF₄ - SF₄ - SiF₄ - BF₄⁻ - BrF₄⁻ - [Cu(NH₃)₄]²⁺ - [FeCl₄]²⁻ - [CoCl₄]²⁻ - [PtCl₄]²⁻ 2. **Analyze Each Compound**: - **XeF₄**: - Xenon (Xe) has 8 valence electrons. - It forms 4 bonds with fluorine and has 2 lone pairs. - The shape is square planar due to the arrangement of 4 bonding pairs and 2 lone pairs. - **SF₄**: - Sulfur (S) has 6 valence electrons. - It forms 4 bonds with fluorine and has 1 lone pair. - The shape is see-saw, not square planar. - **SiF₄**: - Silicon (Si) has 4 valence electrons. - It forms 4 bonds with fluorine and has no lone pairs. - The shape is tetrahedral, not square planar. - **BF₄⁻**: - Boron (B) has 3 valence electrons and gains 1 from the negative charge. - It forms 4 bonds with fluorine and has no lone pairs. - The shape is tetrahedral, not square planar. - **BrF₄⁻**: - Bromine (Br) has 7 valence electrons and gains 1 from the negative charge. - It forms 4 bonds with fluorine and has 2 lone pairs. - The shape is square planar due to the arrangement of 4 bonding pairs and 2 lone pairs. - **[Cu(NH₃)₄]²⁺**: - Copper (Cu) in +2 oxidation state has 9 d-electrons. - It forms 4 bonds with ammonia (NH₃) and undergoes dsp² hybridization. - The shape is square planar. - **[FeCl₄]²⁻**: - Iron (Fe) in +2 oxidation state has 8 d-electrons. - It forms 4 bonds with chloride (Cl) and undergoes dsp² hybridization. - The shape is square planar. - **[CoCl₄]²⁻**: - Cobalt (Co) in +2 oxidation state has 7 d-electrons. - It forms 4 bonds with chloride (Cl) and undergoes sp³ hybridization. - The shape is tetrahedral, not square planar. - **[PtCl₄]²⁻**: - Platinum (Pt) can undergo dsp² hybridization. - It forms 4 bonds with chloride (Cl) and has a square planar shape. 3. **Count the Square Planar Species**: - From the analysis, the species with square planar shape are: - XeF₄ - BrF₄⁻ - [Cu(NH₃)₄]²⁺ - [FeCl₄]²⁻ - [PtCl₄]²⁻ Thus, the total number of species having a square planar shape is **5**. ### Final Answer: The total number of species having a square planar shape is **5**.
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A list of species having the formula XZ_(4) is given below : XeF_(4) ,SF_(4), SiF_(4) ,BF_(4)^(-),BrF_(4)^(-),[Cu(NH_(3))_(4)]^(2+) ,[FeCl_(4)]^(2-) ,CoCl_(4)^(2-) and [PtCl_(4)]^(2-) Defining shape on the basis of the lacation of X and Z atoms , the total number of species having a square planar shape is

A list of species having the formula XZ_(4) is given below XeF_(4),SF_(4),SiF_(4),BF_(4)^(Θ), [Cu(NH_(3))_4]^(2+),[FeCl_(4)]^(2-),[CoCl_(4)]^(2-) and [PtCl_(4)]^(2-) Defining shape on the basis of the location of X and Z atoms , the total number of species having a square planar shape is

Knowledge Check

  • The shape of [PtCl_(4)]^(2-) is

    A
    tetrahedral
    B
    square planar
    C
    linear
    D
    triangular bipyramidal
  • The shape of [Cu(NH_(3))_(4)]^(2+) is

    A
    tetrahedral
    B
    square planar
    C
    pyramidal
    D
    octahedral
  • Among the following the species having square planar geometry for central atom are (i) XeF_(4), (ii) SF_(4) (iii) [NiCl_(4)]^(2-) (iv) [PdCl_(4)]^(2-)

    A
    (i) and (iv)
    B
    (i) and (ii)
    C
    (ii) and (iii)
    D
    (iii) and (iv)
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