In FCC lattice of NaCl structure, if the diameter of `Na^(+)` is `x,` and the radius of `Cl^(-)` is y, then the edge length of the crystal is `:`

Options

A. `2x+2y`
B. `x+2y`
C. `(x)/(2)+y`
D. None of the above.

Answer

B

Explanation

In FCC lattice of NaCl structure `Cl^(-)` are place at the corner of edge length and `Na^(+)` is place at octahedral void `i.e.` middle of two corner `Cl^(-)` ion.