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In FCC lattice of NaCl structure, if the...

In FCC lattice of NaCl structure, if the diameter of `Na^(+)` is `x,` and the radius of `Cl^(-)` is y, then the edge length of the crystal is `:`

A

`2x+2y`

B

`x+2y`

C

`(x)/(2)+y`

D

None of the above.

Text Solution

Verified by Experts

The correct Answer is:
B
In FCC lattice of NaCl structure `Cl^(-)` are place at the corner of edge length and `Na^(+)` is place at octahedral void `i.e.` middle of two corner `Cl^(-)` ion.
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Knowledge Check

  • In foc lattice of NaCl structure, if the diameter of Na^+ is x, and the radius of CI^- is y, then the edge length of NaCl in the crystal is

    A
    2x + 2y
    B
    x + y
    C
    x + 2y
    D
    none of these.

  • If the radius of Cl^(1) ion 181"pm, and the radius of" Na^(+) ion is 101pm then the edge length of unit cel l is:

    A
    282pm
    B
    285.71pm
    C
    512pm
    D
    564pm

  • The radius of Na^(+) is 95pm and that of Cl^(-) is 181 pm. The edge length of unit cell in NaCl would be (pm).

    A
    181
    B
    95
    C
    276
    D
    552

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    The radii of Na^(+) and Cl^(-) ions are 95 pm and 181 pm respectively. The edge length of NaCl unit cell is:

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