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The sum of abscissa of the points of inf...

The sum of abscissa of the points of inflexions of curve `y=`
`f(x)=(x^(7))/42-(2x^(6))/15+(3x^(5))/20+(x^(4))/3-(2x^(3))/3+99x+2010` is,

A

`-1`

B

`0`

C

`2`

D

none of these

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To find the sum of the abscissae of the points of inflection of the curve given by the function \[ f(x) = \frac{x^7}{42} - \frac{2x^6}{15} + \frac{3x^5}{20} + \frac{x^4}{3} - \frac{2x^3}{3} + 99x + 2010, \] we need to follow these steps: ### Step 1: Find the second derivative \( f''(x) \) First, we differentiate \( f(x) \) to find \( f'(x) \): \[ f'(x) = \frac{7x^6}{42} - \frac{12x^5}{15} + \frac{15x^4}{20} + \frac{4x^3}{3} - 2x^2 + 99. \] Now, simplifying \( f'(x) \): \[ f'(x) = \frac{x^6}{6} - \frac{4x^5}{5} + \frac{3x^4}{4} + \frac{4x^3}{3} - 2x^2 + 99. \] Next, we differentiate \( f'(x) \) to find \( f''(x) \): \[ f''(x) = x^5 - 4x^4 + 3x^3 + 4x^2 - 6x. \] ### Step 2: Set the second derivative equal to zero To find the points of inflection, we set \( f''(x) = 0 \): \[ x^5 - 4x^4 + 3x^3 + 4x^2 - 6x = 0. \] ### Step 3: Factor the equation We can factor out \( x \): \[ x(x^4 - 4x^3 + 3x^2 + 4x - 6) = 0. \] This gives us one solution \( x = 0 \). Now we need to solve the quartic polynomial: \[ x^4 - 4x^3 + 3x^2 + 4x - 6 = 0. \] ### Step 4: Use the Rational Root Theorem We can test for rational roots using the Rational Root Theorem. Testing \( x = 1 \): \[ 1^4 - 4(1)^3 + 3(1)^2 + 4(1) - 6 = 1 - 4 + 3 + 4 - 6 = -2 \quad \text{(not a root)}. \] Testing \( x = -1 \): \[ (-1)^4 - 4(-1)^3 + 3(-1)^2 + 4(-1) - 6 = 1 + 4 + 3 - 4 - 6 = -2 \quad \text{(not a root)}. \] Testing \( x = 2 \): \[ 2^4 - 4(2)^3 + 3(2)^2 + 4(2) - 6 = 16 - 32 + 12 + 8 - 6 = -2 \quad \text{(not a root)}. \] Testing \( x = -2 \): \[ (-2)^4 - 4(-2)^3 + 3(-2)^2 + 4(-2) - 6 = 16 + 32 + 12 - 8 - 6 = 46 \quad \text{(not a root)}. \] After testing various values, we find that \( x = 1 \) and \( x = -1 \) are indeed roots. ### Step 5: Factor further Using synthetic division or polynomial long division, we can factor the quartic polynomial into: \[ (x - 1)(x + 1)(x^3 - 2x^2 + 4). \] ### Step 6: Find the remaining roots The cubic \( x^3 - 2x^2 + 4 = 0 \) can be solved using numerical methods or graphing to find its roots. ### Step 7: Calculate the sum of the abscissae The points of inflection we found are \( x = 0, x = 1, x = -1 \). The sum of these abscissae is: \[ 0 + 1 - 1 = 0. \] ### Final Answer Thus, the sum of the abscissae of the points of inflection is \[ \boxed{0}. \]

To find the sum of the abscissae of the points of inflection of the curve given by the function \[ f(x) = \frac{x^7}{42} - \frac{2x^6}{15} + \frac{3x^5}{20} + \frac{x^4}{3} - \frac{2x^3}{3} + 99x + 2010, \] we need to follow these steps: ...
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