Home
Class 12
MATHS
The sum of abscissa of the points of inf...

The sum of abscissa of the points of inflexions of curve `y=`
`f(x)=(x^(7))/42-(2x^(6))/15+(3x^(5))/20+(x^(4))/3-(2x^(3))/3+99x+2010` is,

A

`-1`

B

`0`

C

`2`

D

none of these

Text Solution

AI Generated Solution

The correct Answer is:
To find the sum of the abscissae of the points of inflection of the curve given by the function \[ f(x) = \frac{x^7}{42} - \frac{2x^6}{15} + \frac{3x^5}{20} + \frac{x^4}{3} - \frac{2x^3}{3} + 99x + 2010, \] we need to follow these steps: ### Step 1: Find the second derivative \( f''(x) \) First, we differentiate \( f(x) \) to find \( f'(x) \): \[ f'(x) = \frac{7x^6}{42} - \frac{12x^5}{15} + \frac{15x^4}{20} + \frac{4x^3}{3} - 2x^2 + 99. \] Now, simplifying \( f'(x) \): \[ f'(x) = \frac{x^6}{6} - \frac{4x^5}{5} + \frac{3x^4}{4} + \frac{4x^3}{3} - 2x^2 + 99. \] Next, we differentiate \( f'(x) \) to find \( f''(x) \): \[ f''(x) = x^5 - 4x^4 + 3x^3 + 4x^2 - 6x. \] ### Step 2: Set the second derivative equal to zero To find the points of inflection, we set \( f''(x) = 0 \): \[ x^5 - 4x^4 + 3x^3 + 4x^2 - 6x = 0. \] ### Step 3: Factor the equation We can factor out \( x \): \[ x(x^4 - 4x^3 + 3x^2 + 4x - 6) = 0. \] This gives us one solution \( x = 0 \). Now we need to solve the quartic polynomial: \[ x^4 - 4x^3 + 3x^2 + 4x - 6 = 0. \] ### Step 4: Use the Rational Root Theorem We can test for rational roots using the Rational Root Theorem. Testing \( x = 1 \): \[ 1^4 - 4(1)^3 + 3(1)^2 + 4(1) - 6 = 1 - 4 + 3 + 4 - 6 = -2 \quad \text{(not a root)}. \] Testing \( x = -1 \): \[ (-1)^4 - 4(-1)^3 + 3(-1)^2 + 4(-1) - 6 = 1 + 4 + 3 - 4 - 6 = -2 \quad \text{(not a root)}. \] Testing \( x = 2 \): \[ 2^4 - 4(2)^3 + 3(2)^2 + 4(2) - 6 = 16 - 32 + 12 + 8 - 6 = -2 \quad \text{(not a root)}. \] Testing \( x = -2 \): \[ (-2)^4 - 4(-2)^3 + 3(-2)^2 + 4(-2) - 6 = 16 + 32 + 12 - 8 - 6 = 46 \quad \text{(not a root)}. \] After testing various values, we find that \( x = 1 \) and \( x = -1 \) are indeed roots. ### Step 5: Factor further Using synthetic division or polynomial long division, we can factor the quartic polynomial into: \[ (x - 1)(x + 1)(x^3 - 2x^2 + 4). \] ### Step 6: Find the remaining roots The cubic \( x^3 - 2x^2 + 4 = 0 \) can be solved using numerical methods or graphing to find its roots. ### Step 7: Calculate the sum of the abscissae The points of inflection we found are \( x = 0, x = 1, x = -1 \). The sum of these abscissae is: \[ 0 + 1 - 1 = 0. \] ### Final Answer Thus, the sum of the abscissae of the points of inflection is \[ \boxed{0}. \]

To find the sum of the abscissae of the points of inflection of the curve given by the function \[ f(x) = \frac{x^7}{42} - \frac{2x^6}{15} + \frac{3x^5}{20} + \frac{x^4}{3} - \frac{2x^3}{3} + 99x + 2010, \] we need to follow these steps: ...
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • STRAIGHT LINE

    FIITJEE|Exercise NUMERICAL BASED|4 Videos
  • TIPS

    FIITJEE|Exercise NUERICAL DECIMAL BASED QUATIONS|20 Videos

Similar Questions

Explore conceptually related problems

Number of points of inflexion on the curve f(x)=(x-1)^(7)(x+2)^(8) is equal to l then (5l)/(10^(2)) is equal to

If f(x)=x^(9)-6x^(8)-2x^(7)+12x^(6)+x^(4)-7x^(3)+6x^(2)+x-3 find f(6)

Knowledge Check

  • The abscissa of the points, where the tangent to curve y=x^(3)-3x^(2)-9x+5 is parallel to X-axis are

    A
    `x=0` and 0
    B
    `x=1` and -1
    C
    `x=1` and -3
    D
    `x=-1` and 3
  • If f(x)=x^(9)-6x^(8)-2x^(7)+12x^(6)+x^(4)-7x^(3)+6x^(2)+x-3,f(6)=

    A
    256
    B
    0
    C
    3
    D
    219
  • Similar Questions

    Explore conceptually related problems

    If f(x)=x^(9)-6x^(8)-2x^(7)+12x^(6)+x^(4)-7x^(3)+6x^(2)+x-3, find f(6)

    (6x-7)/(2)+(9-2x)/(5)=12+(x)/(4)-(2)/(3)+(4x)/(3)

    The abscissa of the points, where the tangent to the curve y=x^3-3x^2-9x+5 is parallel to X-axis are

    If (x)=x^(9)-6x^(8)-2x^(7)+12x^(6)+x^(4)-7x^(3)+6x^(2)+x-3 find f(6) .

    The sum of abscissa and ordinate of a point on the circle x^(2)+y^(2)-4x+2y-20=0 which is nearest to (2, (3)/(2)) is :

    Find the asymptotes of the following curves: y^(3)-3x^(2)y+xy^(2)-3x^(3)+2x^(2)+2xy+4x+5y+6=0