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Figure shows two blocks in contact slidi...

Figure shows two blocks in contact sliding down an inclined surface of inclination 30º. The friction coefficient between the block of mass 2.0 kg and the incline is μ1, and that between the block of mass 4.0 kg and the incline is μ2. Calculate the acceleration of the 2.0 kg block if μ1 = 0.30 and μ2 = 0.20, Take g = 10 m/s2

Text Solution

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The correct Answer is:
(a) constant force = 0 , acceleration of 4 kg block is `0.7 m//s^(2)` and that of other block is zero
(b) constant force 1.4 N , acceleration of both =0
(c) Constant force = 5.74 N , acceleration of both = `1.27 m//s^(2)`
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Knowledge Check

  • A block of mass m slides down an inclined plane of inclination theta with uniform speed The coefficient of friction between the block and the plane is mu . The contact force between the block and the plane is .

    A
    `mg sin thetasqrt(1+mu^(2))`
    B
    `sqrt((mg sin theta)^(2)+(mumgcostheta)^(2))`
    C
    `mg sin theta`
    D
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    B
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    C
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