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A hydrogen like atom (atomic number = Z)...

A hydrogen like atom (atomic number = Z) is in higher excited state of quantum number n. This excited atom can make a transition to first excited state by successively emitting two photons of energy `22.94 eV` and `5.15 eV`. The atom from the same state n can make transition to second excited state by successively emitting two photons of energies `2.4 eV` and `8.7 eV`. Find values of n and Z.

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The correct Answer is:
`n = 7 ; Z = 3`
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