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In the pulley system shown here, find th...

In the pulley system shown here, find the relationship between acceleration of `m_(1),m_(2)` and `m_(3)`

A

`2a_(1)+a_(3)+a_(1)=0`

B

`2a_(2)-a_(3)+a_(1)=0`

C

`2a_(2)+a_(3)-a_(1)=0`

D

`2a_(2)-a_(3)-a_(1)=0`

Text Solution

Verified by Experts

The correct Answer is:
C

`Ta_(1)-Ta_(2)-2Ta_(2)=0`
`rArr a_(1)-a_(3)-2a_(2) =0`
`rArr 2a_(2)+a_(3)-a_(1)=0`
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Knowledge Check

  • A pulley-block arrangement is shown in the adjacent figure, if acceleration of m_(1), m_(2) and m_(3) are a_(1) ,a_(2) and a_(3) respectively, then relation between a_(1),a_(2) and a_(3) is ( All string and pulleys are ideal . )

    A
    `a_(2) - a_(3) + 10 a_(1) = 0`
    B
    `a_(3) - a_(2) + 10 a_(1) = 0`
    C
    `a_(2) - 2a_(3) + 10a_(1) = 0`
    D
    `2a_(2) + a_(3) + 5a_(1) = 0`

  • If system is in equilibrium then find relation between m_(1) and m_(2)

    A
    `(m_(1))/(m_(2))=(1)/(2)`
    B
    `(m_(1))/(m_(2))=(1)/(15)`
    C
    `(m_(1))/(m_(2))=(1)/(10)`
    D
    `(m_(1))/(m_(2))=1`

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