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From a circular disc of radius R, a tria...

From a circular disc of radius `R`, a triangular portion is cut (sec figure). The distance of the centre of mass of the remainder from the centre of the disc is `-`

A

`(4R)/(3(pi-2))`

B

`(2R)/(3(pi-2))`

C

`(5R)/(7(pi-2))`

D

`(R)/(3(pi-1))`

Text Solution

Verified by Experts

The correct Answer is:
D
Ans.(4)
Lot mass per area be `sigma`

`Y_(cm)=(M_(1)(0)-M_(2)((R)/(3)))/(M_(1)-M_(2))=(-R)/(3(pi-1)`
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