Home
Class 11
PHYSICS
Throughout a time interval, while the sp...

Throughout a time interval, while the speed of a particle increases as it moves along x-axis, its velocity and acceleration might be

A

positive and positive respectively

B

positive and negative respectively

C

negativetive and negative respectively

D

negative and positive respectively

Text Solution

Verified by Experts

The correct Answer is:
A, C
Spped increases if both velocity & acceleration have same signs.
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • KINEMATICS

    ALLEN|Exercise EXERCISE-01|55 Videos

  • KINEMATICS

    ALLEN|Exercise EXERCISE-02|57 Videos

  • ERROR AND MEASUREMENT

    ALLEN|Exercise Part-2(Exercise-2)(B)|22 Videos

  • KINEMATICS (MOTION ALONG A STRAIGHT LINE AND MOTION IN A PLANE)

    ALLEN|Exercise BEGINNER S BOX-7|8 Videos

Similar Questions

Explore conceptually related problems

A particle confined to motion along an x axis moves with constant acceleration from x=2.0m to x=8.0 m during a 2.5 s time interval. The velocity of the particle at x=8.0m is 2.8 m/s. What is the constant acceleration during this time interval ?

A particle experience an acceleration a=(4e^(-3t))m/s^(2) along positive x-axis, where t is time in s .If the initial velocity of the particle is 2m/s along positive x-axis,the velocity of the particle when its acceleration becomes zero is?

Knowledge Check

  • If v is the velocity of a body moving along x-axis, then acceleration of body is

    A
    `(dv)/(dx)`
    B
    `v(dv)/(dx)`
    C
    `x(du)/(dx)`
    D
    `v(dx)/(dv)`

  • The displacement of a particle moving along x-axis is given by : x = a + bt + ct^2 The acceleration of the particle is.

    A
    b
    B
    c
    C
    `b + c`
    D
    2 c

  • The speed of a particle moving in a circle is increasing. The dot product of its acceleration and velocity is

    A
    negative
    B
    zero
    C
    positive
    D
    may be positive or negative

    • Similar Questions

    Explore conceptually related problems

    A particle experience an acceleration a=(4e^(-3t)) ,m/ s^(2) along positive x-axis,where t is time in s.If the initial velocity of the particle is 2m/s along positive x -axis,the velocity of the particle when its acceleration becomes zero is ?

    The velocity-position graph of a particle moving in a straight line along x -axis is givenbelow.Acceleration of particle,at x=2m is

    Assertion : A particle moves along circular path with constant speed then acceleration must be present. Reason : A particle moves with variable velocity then acceleration must be present.

    If a particle is moving along straight line with increasing speed, then

    Assertion: In successive time intervals if the average velocities of a particle are equal then the particle must be moving with constant velocity. Reason: When a particle moves with uniform velocity, its displacement always increases with time.

    Home
    Profile