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The mass of proton is 1.0073 u and that ...

The mass of proton is `1.0073 u` and that of neutron is `1.0087 u` (`u=` atomic mass unit). The binding energy of `._(2)He^(4)` is (mass of helium nucleus `=4.0015 u`)

A

`28.4` MeV

B

`0.061 u`

C

`0.0305 J`

D

`0.0305` erg

Text Solution

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The correct Answer is:
To find the binding energy of the helium-4 nucleus, we will follow these steps: ### Step 1: Identify the Composition of Helium-4 Helium-4 (²He⁴) consists of: - 2 protons - 2 neutrons ### Step 2: Calculate the Mass of Protons The mass of one proton is given as \(1.0073 \, u\). Therefore, the total mass of 2 protons is: \[ \text{Mass of protons} = 2 \times 1.0073 \, u = 2.0146 \, u \] ### Step 3: Calculate the Mass of Neutrons The mass of one neutron is given as \(1.0087 \, u\). Therefore, the total mass of 2 neutrons is: \[ \text{Mass of neutrons} = 2 \times 1.0087 \, u = 2.0174 \, u \] ### Step 4: Calculate the Total Mass of Protons and Neutrons Now, we can find the total mass of the helium nucleus (protons + neutrons): \[ \text{Total mass} = \text{Mass of protons} + \text{Mass of neutrons} = 2.0146 \, u + 2.0174 \, u = 4.032 \, u \] ### Step 5: Calculate the Mass Defect The mass defect (\(\Delta m\)) is the difference between the total mass of the individual nucleons and the actual mass of the helium nucleus: \[ \Delta m = \text{Total mass} - \text{Mass of helium nucleus} = 4.032 \, u - 4.0015 \, u = 0.0305 \, u \] ### Step 6: Convert Mass Defect to Energy To find the binding energy, we use the formula: \[ \text{Binding Energy} = \Delta m \times c^2 \] Where \(c^2\) in terms of atomic mass units can be converted to MeV using the conversion factor \(931 \, \text{MeV/u}\): \[ \text{Binding Energy} = 0.0305 \, u \times 931 \, \text{MeV/u} = 28.4 \, \text{MeV} \] ### Final Answer The binding energy of the helium-4 nucleus is approximately \(28.4 \, \text{MeV}\). ---
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The atomic mass . _2^4He is 4.0026 u and the atomic mass of ._1^1H is 1.0078 u . Using atomic mass units instead of kilograms, obtain the binding energy of ._2^4He nucleus.

Mass of Helium nucleus = 4 . 00015 amu and mass of a proton =1 .0073 amu mass of neutron= 1.0087 amu Calculate the mass defect and energy liberated in formation of He nucleus and also evaluate binding energy of ._(2)He^(4) nucleus.

Knowledge Check

  • The mass of proton is 1.0073 u and that of neutron is 1.0087 u ( u=atomic mass unit ). The binding energy of ._2^4He , if mass of ._2^4He is 4.0015 u is

    A
    0.0305 erg
    B
    0.0305 J
    C
    28.4 MeV
    D
    0.061 u
  • If the mass of proton= 1.008 a.m.u. and mass of neutron=1.009a.m.u. then binding energy per nucleon for ._(4)Be^9 (mass=9.012 amu) would be-

    A
    0.065 MeV
    B
    60 .44MeV
    C
    0.7 MeV
    D
    6.72 MeV
  • One atomic mass unit (u) is equivalent to an energy of :

    A
    931 eV
    B
    9.31 MeV
    C
    1 MeV
    D
    931 MeV
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