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In a parallel plate capaacitor with air ...

In a parallel plate capaacitor with air between the plates, each plate has an area of `6xx10^(-3) m^2` and the distance between the plates is 3mm. Calculate the capacitance of the capacitor. If this capacitor is connected to a 100V supply, what is the charge on each plate of the capacitor?

Text Solution

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`alpha = 6xx10^(-3) m^2, d=3mm = 3xx10^(-3)m, V =100V`
`C_0 = (in_0 alpha)/(d) = ((8.85xx10^(-12))(6xx10^(-3)))/(3xx10^(-3)) = 1.77xx10^(-11)F`
`q = C_0V = 1.77xx10^(-11)xx100 = 1.77xx10^(-9)C`.
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In a parallel plate capacitor with air between the plates, each plate has an area of 6 xx 10^(-3)m^(2) and the distance between the plates is 3 mm. Calculate the capacitance of the capacitor. If this capacitor is connected to a 100 V supply, what is the charge on each plate of the capacitor?

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Knowledge Check

  • If the distance between the plates of a parallel plate capacitor is doubled while the battery is kept connected, then

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    the charge stored in the capacitor will be doubled
    B
    the battery will absorb some amount of energy
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    the electric field between the two plates will be halved
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    work will be done by an external agent on the two plates

  • A parallel plate capacitor has a uniform electric field E in the space between the plates. If the distance between the plates is d and area of each plate is A, energy stored in the capacitor is

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    D
    `epsilon_0EAd`

  • The capacitance of a parallel plate capacitor depends on

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    the thickness of the plates
    B
    the charge accumulated on the plates
    C
    the potential difference between the two plates
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