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A capacitor C1 of capacitance 5muF is ch...

A capacitor `C_1` of capacitance `5muF` is charged to a potetntial of 100V and another capacitor `C_2` of capacitance `8muF` is charged to 50V. The positive and negative plates are mutually connected.
The final potential of the combination of the two capacitance will be

A

`(500)/(3)V`

B

`(900)/(13)V`

C

`150 V`

D

`50 V`

Text Solution

Verified by Experts

The correct Answer is:
B
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Knowledge Check

  • A capacitor C_1 of capacitance 5muF is charged to a potetntial of 100V and another capacitor C_2 of capacitance 8muF is charged to 50V. The positive and negative plates are mutually connected. Amount of charge of the capacitor C_1 after combination will be

    A
    `(4500)/(13) muC`
    B
    `(7200)/(13) muC`
    C
    `(2700)/(13) muC`
    D
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  • A capacitor C_1 of capacitance 5muF is charged to a potetntial of 100V and another capacitor C_2 of capacitance 8muF is charged to 50V. The positive and negative plates are mutually connected. Amount of charge of the capacitor C_2 after combination will be

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    `4500muC`
    B
    `7200muC`
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    `(4500)/(13)muC`
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  • A capacitor of capacitance C_1 is charged up to potential V and then connected in parallel to an uncharged capacitor or capacitance C_2 . The final potential difference across each capacitor will be

    A
    `(C_2V)/(C_1+C_2)`
    B
    `(C_1V)/(C_1+C_2)`
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