Two cities are 150 km apart . Electric power is sent from one city to another city through copper wires . The fall of potential per km is 8 volt and the averge resistance per km is `0.5Omega` .The power loss in the wire is
Two cities are 150 km apart . Electric power is sent from one city to another city through copper wires . The fall of potential per km is 8 volt and the averge resistance per km is `0.5Omega` .The power loss in the wire is
A
`19.2W`
B
`19.2kW`
C
`19.2J`
D
`12.2kW`
Text Solution
Verified by Experts
The correct Answer is:
B
Total resistance `=0.5xx150=75Omega`
Total voltage drop `=8xx150=1200V`
`therefore` power dissipated
`=(V^(2))/(R)=(1200)^(2)/(75)=19200W=19.2kW`
Total voltage drop `=8xx150=1200V`
`therefore` power dissipated
`=(V^(2))/(R)=(1200)^(2)/(75)=19200W=19.2kW`
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A small town with a demand of 800 kW of electric power at 220 V is situated 15 km away from an electric plant generating power at 440 V. The resistance of the two wire line carrying power is 0.5 Omega per km. The town gets power from the line through a 4000-220 V step-down transformer at a sub-station in the town. (a) Estimate the line power loss in the form of heat. (b) How much power must the plant supply, assuming there is negligible power loss due to leakage? (c) Characterise the step up transformer at the plant.
A small town with a demand of 800 kW of power at 220 V is situated 15 km away from an electric plant generating power at 440 V. The resistance of the two wire line carrying power is 0.5Omega . km^-1 . The line gets power from the line through a 4000-220 V step-down transformer at a substation in the town. How much power must the plant supply, assuming there is negligible power loss due to leakage.
Knowledge Check
Let us take an electrical conductor in which the electrical energy supplied is entirely converted into heat . If , for the conductor , the terminal potential difference = V , the curent through it = I and its resistance = R , then the electrical energy cnsumed in its t is , W=I^(2)t (from Ohm'slaw R=(V)/(I) ) . So , if thr electrical and the heat energies both are expressed in joule , the heat developed in tiem t is H=I^(2)Rt . However , If H is expressed in the conventional unit calorie , then from the law , W = JH , we may write H=(I^(2)Rt)/(J) , where , J = mechanical equivalent of heat =4.2J."cal"^(-1) . The resistance R of a conducting wire depends on its material , its length l and its area of cross section a .The resistivity of the meterial of the conductor is , rho=(RA)/(l) . When more than one heat -producing conductors are kept in series in a circuit , the same current passes through each of them , but as their resistance are f=different in general , the terminal potential differences are also unequal . On the other hand , each conductor has the same terminal potential difference in a parallel combination , however , the curents through them are different . The terminal potential difference and the currents through two conducting wires are both in the ratio 2 : 1 The ratio of the rates of heat evolved in them is
Let us take an electrical conductor in which the electrical energy supplied is entirely converted into heat . If , for the conductor , the terminal potential difference = V , the curent through it = I and its resistance = R , then the electrical energy cnsumed in its t is , W=I^(2)t (from Ohm'slaw R=(V)/(I) ) . So , if thr electrical and the heat energies both are expressed in joule , the heat developed in tiem t is H=I^(2)Rt . However , If H is expressed in the conventional unit calorie , then from the law , W = JH , we may write H=(I^(2)Rt)/(J) , where , J = mechanical equivalent of heat =4.2J."cal"^(-1) . The resistance R of a conducting wire depends on its material , its length l and its area of cross section a .The resistivity of the meterial of the conductor is , rho=(RA)/(l) . When more than one heat -producing conductors are kept in series in a circuit , the same current passes through each of them , but as their resistance are f=different in general , the terminal potential differences are also unequal . On the other hand , each conductor has the same terminal potential difference in a parallel combination , however , the curents through them are different . The terminal potential difference and the currents through two conducting wires are both in the ratio 2 : 1 The ratio of the rates of heat evolved in them is
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D
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Let us take an electrical conductor in which the electrical energy supplied is entirely converted into heat . If , for the conductor , the terminal potential difference = V , the curent through it = I and its resistance = R , then the electrical energy cnsumed in its t is , W=I^(2)t (from Ohm'slaw R=(V)/(I) ) . So , if thr electrical and the heat energies both are expressed in joule , the heat developed in tiem t is H=I^(2)Rt . However , If H is expressed in the conventional unit calorie , then from the law , W = JH , we may write H=(I^(2)Rt)/(J) , where , J = mechanical equivalent of heat =4.2J."cal"^(-1) . The resistance R of a conducting wire depends on its material , its length l and its area of cross section a .The resistivity of the meterial of the conductor is , rho=(RA)/(l) . When more than one heat -producing conductors are kept in series in a circuit , the same current passes through each of them , but as their resistance are f=different in general , the terminal potential differences are also unequal . On the other hand , each conductor has the same terminal potential difference in a parallel combination , however , the curents through them are different . Heat is produced at hte rate of 8"cal".s^(-1) in a uniform wire , when its terminal potential difference is 10 V What would be the rate in another wire of the same material , of the same potential difference ?
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A
`32"cal".s^(-1)`
B
`16"cal".s^(-1)`
C
`4"cal".s^(-1)`
D
`2"cal".s^(-1)`
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