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Two charged particles traverses indentic...

Two charged particles traverses indentical helical paths in a completely opposite sense in a uniform magnetic field, `vecB=B_(0)hatK`.

A

they have equal z-componenets of momenta

B

they must have equal charge

C

they necessarily represent a particle-antipartile pair

D

the charge to mass ratio satisfy `((q)/(m))_(1)+((q)/(m))_(2)=0`

Text Solution

Verified by Experts

The correct Answer is:
D

The radius of the helical path, `r=(v sin theta)/(((q)/(b))B)` and the displacement of the charged paritcle along the magnetic field is one rotation
`=(2pi v cos theta)/(((q)/(m))B)`
Two charged particles will traverse indentical path in opposite sense is `(q)/(m)` for the both the particles is same and opposite.
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Knowledge Check

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    A
    Path of the particle is helix
    B
    Path of the particle of circle
    C
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    D
    Velocity of the particle after time t= `pi/(B_0alpha)` is ((v_0/2)hati+(v_0/3)hatj)`
  • Two identical particles having the same mass m and charges +q and -q seprately by a distance d in a uniform magnetic field B directed perpendicular to paper inwards with speed v_1 and v_2 as shown in figure the particles will not colloid if

    A
    `dgt(m)/(Bq)(v_1+v_2)`
    B
    `dlt(m)/(Bq)(v_1+v_2)`
    C
    `dgt(2m)/(Bq)(v_1+v_2)`
    D
    `v_1-v_2`
  • A charge particle travels along a straight lines with a speed nu in a region where both electric field E and magnetic field B are present it follows that

    A
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    B
    `absE=nu absB` and the two fields are perpendicular
    C
    `absB= nu absE` and the two fields are parallel
    D
    `absB= nu abs E` and two fields are perpendicular
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