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A screen is placed 40 cm from a narrow s...

A screen is placed 40 cm from a narrow slit. Parallel light rays of wavelength 5890 Å fall on the slit. First minimum is formed 2 mm on either side of central maximum.Find the width of the narrow slit.

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The correct Answer is:
0.12 cm
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For producing a fraunhofer diffraction fringe, a screen is placed 2m away from a single narrow slit. If the width of slit is 0.2 mm, it is found that first minimum lies 5 mm on either side of the central maximum. Find the wavelength of the incident light.

A narrow slit of width d is placed in front of a convex lens of focal length 0.5 m. the slit is illuminated normally by a light of wavelength 5.89 xx 10^(-7) m. If the distance between two first minima on the either side of central maximum is 2xx10^(-3) m, calculate the width d of the slit.

Knowledge Check

  • A slit of width a is illuminated by red light of wavelength 650 nm. The first diffraction minimum is observed at an angle theta_(1) = 5.2^(@) from the direction of the incident beam. The width of the slit a in mm is

    A
    `5.12xx10^(-3)`
    B
    `7.17xx10^(-3)`
    C
    `3.21 xx 10^(-7)`
    D
    `4.25 xx 10^(-7)`

  • In an ideal double slit experiment when a glass plate having refractive index 1.5 and thickness t is placed in the path of interfered light rays of wavelength lambda then the intensity remains unchanged at the place where the central maximum was previously formed. Then the minimum thickness of the glass plate is

    A
    `2 lambda`
    B
    `(2 lambda)/(3)`
    C
    `(lambda)/(3)`
    D
    `lambda`

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